von Mark Kirtley
8 - Gianni Donati
Probleemblad, 1999
13+15. a) Beweispartie in 5.5 Zügen b) Beweispartie in 6.0 Zügen
[rnbqkb1r/pppppppp/8/8/8/8/PP2PPPP/R1BQKBNR]
Lösung
1. Bd2-d4 Sg1-h6 2. Sb1-d2 Sh6-f5 3. Sd2-f3 Sf5:Bd4 4. Ke1-d2 Sd4:Bc2 5. Sf3-e1 Sc2:Se1 6. Kd2:Se1
1. Bc2-c3 Sg8-f6 2. Bc3-c4 Sf6-e4 3. Bc4-c5 Se4:Bd2 4. Bc5-c6 Sd2:Sb1 5. Ta1:Sb1 Sb8:Bc6 6. Tb1-a1 Sc6-b8
