No. 252, December 2011
15066 - Joaquim Crusats, Andrej N. Frolkin
Die Schwalbe, No. 252, 12/2011
12+11. Shortest mate?
[RBb1k2r/1pPppprB/p2P1Pp1/2P4P/1P4p1/8/7P/4K2R]
Solution
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15067 - Nikolai Beluchow
11+7. Two chess positions have been rotated randomly and then merged into one diagram. No two pieces share the same square. What are the two original positions?
(Zufällig wurden zwei Schachstellungen jeweils verdreht und dann in einem Diagramm gedruckt. Keine zwei Steine wurden übereinander gedruckt. Was waren die beiden Stellungen?)
[1q3q1q/8/1q3Q1K/4N1N1/5q2/2RQ1k1Q/1K3P2/3Q1k1Q]
15068 - Michel Caillaud
Dedicated to Wolfgang Dittmann
11+9. Retract 8 moves, then #1 (Proca-Retractor)
[R7/1pp1ppP1/1p2ppPk/B4p2/B2P1K1P/2P2P2/6P1/8]
15069 - Mario Richter, Zalmen Kornin
10+8. (-2s, -1w), then H#2 (Help Retractor)
[2b2k2/8/8/8/N1pp4/1p2p3/PPPPPPPP/K2n2n1]
15070 - Peter Heyl
16+12. Proof game in 8.0 moves
[2k2bnr/p3pppp/rp6/2p5/8/8/PPPPPPPP/RNBQKBNR]
Solution Replay
1. Sf3 c5 2. Se5 Dc7 3. Sxd7 De5 4. Sxb8 Ld7 5. Sxd7 0-0-0 6. Sxe5 Td6 7. Sf3 Ta6 8. Sg1 b6
15071 - Silvio Baier
16+14. Proof game in 23.5 moves
[2bq1b2/2ppp3/n6n/5p2/1Pk4r/1nr5/RrPPPPPR/RNBQKBNR]
1.h4 f5 2.h5 Kf7 3.h6 Ke6 4.hxg7 h5 5.Th3 h4 6.Tb3 h3 7.a4 h2 8.a5 h1=T 9.Ta4 T1h3 10.Th4 Tc3 11.Th1 Th4 12.a6 Sh6 13.axb7 a5 14.g8=T a4 15.Tg3 a3 16.Tgh3 a2 17.Ta3 a1=S 18.b4 Sb3 19.Ta1 Ta2 20.T3h2 Sa6 21.b8=T Kd5 22.Tb5+ Kc4 23.Tba5 Tb2 24.T5a2
15072 - Silvio Baier
13+12. Proof game in 29.0 moves
[rnbqkbnr/2ppp3/2RPp3/2K1P3/1P5B/3P1R2/N2PB3/2NQ4]
1.e4 b5 2.Ke2 b4 3.Ke3 b3 4.Se2 bxa2 5.b4 g5 6.Lb2 g4 7.Lf6 g3 8.Sbc3 gxh2 9.Tc1 a1=D 10.g4 Da6 11.g5 Dd3+ 12.cxd3 a5 13.g6 a4 14.g7 a3 15.gxf8=S a2 16.Se6 a1=L 17.Sa2 h5 18.Tc6 h4 19.Sec1 h3 20.Lh4 Lg7 21.Le2 Lf8 22.Tf1 h1=D 23.e5 Dd5 24.f4 Dd6 25.exd6 h2 26.Kd4 h1=D 27.Kc5 De4 28.Tf3 De5+ 29.fxe5 fxe6
15073 - Bernd Gräfrath, Wolfgang Dittmann, Mario Richter
15+15. Single Combat Chess. What is the minimum number of a) black b) white knight moves?
[r1bqkbnr/pppppppp/8/8/2P5/6P1/PP1PPPP1/RNBQK1NR]
Author's solution: a) = 26, b) = 0