No. 238, August 2009

14182 -

Die Schwalbe 238, August 2009

+bRh6, +bSf2 and -1...Rh1-h6 -2. a4-a5 Rb1-h1 -3. a3-a4 Rb6-b1 -4.
a2-a3

Rb1xb6 -5. b5-b6 Sh1-f2 -6. b4-b5 h2-h1=S -7. b3-b4 h3-h2 -8. b2-b3

h4-h3 -9. e4-e5 h5-h4 -10. e3-e4 h6-h5 -11. h5xSg6 etc

14183 -

Die Schwalbe 238, August 2009

Try: -1. e7-e8=S and 1. e8=R/Q#, but 9 white pawns

Try: -1. d2xSc3 & d4#. White needs 6 captures for the pawn structure, and with Bc8 this means all missing black pieces. So black needs 6 pawn captures too for his pawn structure, since g2 can't have come from g7 without a capture. But Bc1 isn't available for capture, so this results in an illegal position.

Solution: -1. f2xSg3 & 1. f4#

14184 -

Die Schwalbe 238, August 2009

1. e4 Nf6 2. Qh5 Rg8 3. Qh6 gxh6 4. a4 Rg3 5. Ra2 Ra3 6. g4 Bg7 7. g5 Ng4 8. g6 Bc3 9. g7 Ba5 10. b4 d6 11. Bb2 Be6 12. g8=Q+ Kd7 13. Bh8 Bb3 14. Qg7 Ke6 15. Qa1 Nd7 16. Nc3 Ndf6 17. Bc4+ Ke5 18. Bd5 Kf4 19. Nge2+ Kf3 20. O-O Qg8 21. Rb1 Qg5 22. Rbb2 Rg8 23. Qd1 Rg6 24. Nb1 Ng8 25. Bc3 Rf6 26. Kh1

Pronkin queen, sibling knight, switchback

14185 -

Die Schwalbe 238, August 2009

Intentions: -1. bSe4xwSc5 and 1. Rf8 Kc8 2. Sd6 e6#; -1. Qe4xQb7 and 1. Qb1 Qf3 2. Qb8 Qf4#

But the first one doesn't work (the retraction is illegal), plus this is horribly cooked, e.g. -1. Sg1xQf3 & 1. Sh3 Sf5 2. Ra2 Qg3#

14186 -

Die Schwalbe 238, August 2009

-1. Kf3-g2 Rf7-g7 -2. Ke3-f3 Re7-f7 -3. Kd3-e3 Rd7-e7 -4. Kc3-d3 Rc7-d7 -5. Be8xSa4[Bf1] Sb2-a4 -6. Kd3-c3 Rd7-c7 -7. Ke3-d3 Re7-d7 -8. Kf3-e3 Rf7-e7 -9. Rg2-f3 Rg7-f7 -10. Rh5-e5 & 1. Rh8#

Cook, found by Mario Richter: -1. Rh5-e5!! ~ 2. Be8xXf7[Bf1] & 1. Rh5-h8#. Nothing black does on his first move can avoid this short solution.

Correction: bRg6 instead of bPg6.

14187c -

Die Schwalbe 238, August 2009

a) Possible proofgame: 1. Nf3 Nf6 2. Nd4 Rg8 3. Ne6 Rh8 4. h4 Rg8 5. Rh3 Rh8 6. Rg3 Ne4 7. Rg6 hxg6 8. Nxf8 Rh6 9. h5 Rh7 10. h6 Rh8 11. h7 Rg8 12. h8=R Ng3 13. Rh4 Rh8 14. Ne6 Nh5 15. Nd4 Kf8 16. Nf3 Kg8 17. Ng1 Kh7 18. Rh3 Rf8 19. Rh1 Kh8

b) 1. h4 Sf6 2. h5 Sh8[g8=R] 3. Rf8[-] Kf8[Rh6] 4. Rh7[Pg6] Kg8 5. Rh8[Rf8] Kh8[-]

14188 -

Die Schwalbe 238, August 2009

1. a3 b5 2. c4 bc4 3. Qb3 cb3 4. Ra2 ba2 5. Sc3 a1=K 6. b3 Bb7 7. Bb2 Bg2 8. Ba1

Fastest King-Schnoebelen in losing chess

14189 -

Die Schwalbe 238, August 2009

1. e4 d5 2. ed5 Sc6 3. dc6 Qd5 4. cb7 Qa2 5. bc8=S! Qe6 6. Se2 Qe3 7. h3 Qd2 8. Sd2 c5 9. Sc4 Rc8 10. Sb6 Rb8 11. Sc8

Schnoebelen-knight and antipronkin knight on c8.

14190 -

Die Schwalbe 238, August 2009

Inspired by A.C. Jobim

Dedicated to Enzo Minerva and the Rio 2009 meeting

1. h4 g5 2. hg5[Pg7] b6 3. Rh6 Ba6 4. Rb6[Pb7] h5 5. e4 Rh6 6. Qh5[Ph7] Rc6 7. Sf3 Rc3 8. Bc4 d5 9. d3 Qd7 10. Sbd2 Qa4 11. Sb3 Sc6 12. Bd2 OOO 13. Qh3 f5 14. ef6[Pf7] Kb8 15. fe7 Ka8 16. e8=R Re8[Rh1] 17. OO Bc5 18. ed5[Pd7] Re1 19. Kh1 Rf1

All four special moves (doublestep, en passant, promotion, castling) performed by Ph2.

14191 -

Die Schwalbe 238, August 2009

Place one white bishop and two white knights on an empty board so they have exactly 28 move possibilities. How many solutions?

A bishop has maximum 13 moves, and a knight maximum 8. The wanted number of moves is one less than the maximum, so a knight must guard the bishop. So on the board is a bishop that has 13 moves, one knight that has 8 and one that has 7 moves.

The bishop is on one of the center squares. Take e.g. e5. There are only 6 squares where the '8-knight' can be: d5, e4, f5, e6, c5, e3. With the first four squares, the second knight must be on c6, c4, d3 or f3. With the other two squares, the second knight must be on c6, (d3 or c4) and f3. In total that is 4*4+2*3=22. The same number is reached for the other three central squares where the bishop can be. So the number of positions is 88.

14192 -

Die Schwalbe 238, August 2009

Place the seven white officers on an empty board. The bishops are on a1 and h1, the rooks and the queen on a square on the first row, and the knights on random squares. White has exactly 64 move possibilities. How many solutions?

The maximum is reached when there are two major officers on b1 and g1, and the knights have 8 moves without blocking white lines. With a rook on g1, the different positions are:

Qb1, Rc1: knights on d6, e3, e6, f4 (except the combination e6/f4): 5 positions

Qb1, Rd1: knights on c4, c5, e6, f4 (except the combinations e6/f4 and c5/e6): 4 positions

Qb1, Re1: knights on c4, c5, d6, f4 (except the combination c4/d6): 5 positions

Qb1, Rf1: knights on c4, c5, d6, e6 (except the combinations c4/d6 and c5/e6): 4 positions

Qc1, Rb1: knights on d6, e6, f5 (except the combination d6/f5): 2 positions

Qd1, Rb1: knights on c4, c5, e6, f4, f5 (except the combinations c5/e6 and e6/f4): 8 positions

All these positions can be mirrored, so the total is 2*(5+4+5+4+2+8)=56