Die Schwalbe

No. 233, October 2008

Here are the compositions in the originals section from Die Schwalbe 233, Oct. 2008. I received a correction from Werner Keym for 13890, so the text given here is different from the text in the issue itself!

13879 - Werner Keym

Die Schwalbe, October 2008

13+12. #3

[r3k2r/bRp1p1p1/1pn1P2B/rB2p3/n1P1Q3/2P1P3/1P4P1/R3K2R]

Solution

13880 - Thierry le Gleuher

Die Schwalbe, October 2008

(Misprint fixed; in the printed diagram there was an wPe7 instead of a wBe7)

16+10. Last 36 single moves?

[1Qk5/1bPNB1N1/BrpRRQN1/1p1ppRQ1/7B/5pB1/5PpK/7b]

Solution

13881 - Gianni Donati, Olli Heimo

Die Schwalbe, October 2008

Dedicated to Günter Lauinger

14+15. PG in 19.0 moves

[1nrq2k1/1p2np1p/3b4/1p1pp1p1/b7/2PK1Pr1/PPQ1P1PP/RNB3NR]

Solution

13882 - Bernd Gräfrath

Die Schwalbe, October 2008

15+15. Shortest proof game? a) Orthodox b) Losing chess

[r1b1kbnr/ppBppppp/8/q1p5/8/3P4/PPPKBPPP/RN3QNR]

Solution

13883 - Bernd Gräfrath

Die Schwalbe, October 2008

13+13. PG in 8.0 moves (Losing chess)

[rnb1kb1q/pppp1p2/7p/4p3/6P1/8/PPPPP3/RNBQK1NB]

Solution

13884 - Bernd Schwarzkopf

Die Schwalbe, October 2008

7+8. #3 (maximummer)

[r3k3/pppb2pp/8/8/P5R1/6P1/5P1P/R3K3]

Solution

13885 - Tadashi Wakashima

Die Schwalbe, October 2008

2+1. -2 & #1, Proca retractor, transmuting kings

[4k2K/4P3/8/8/8/8/8/8]

Solution

13886 - Günther Weeth, Klaus Wenda

Die Schwalbe, October 2008

6+7. -5 & s#1, Proca retractor, Anticirce

[8/2k5/Q7/6p1/5b2/5r2/2n2PP1/n1Rb1BK1]

Solution

13887 - Mario Richter

Die Schwalbe, October 2008

9+3. Last move, type D (Isardam)

[8/8/8/8/8/PPPP4/r1QpPP2/k1RK4]

Solution

13888 - Bernd Schwarzkopf, Werner Keym

Die Schwalbe, October 2008

7+4. Equal last move

[5KNk/5p1q/5P1Q/5PPP/6p1/8/8/8]

Solution

13889 - Werner Keym, Bernd Schwarzkopf

Die Schwalbe, October 2008

Original text: Konstruiere ein Illegal Cluster mit wKDTLLBBBBBB(11) und bK(1). Auf zwei benachbarten Reihen stehen jeweils ausschlie?#376;lich fünf Offiziere und fünf Bauern fron Wei?#376;.

Translation: Construct an Illegal Cluster with wKQRBBPPPPPP(11) and bK(1). On two adjacent rows stand respectively 5 white officers and 5 white pawns.

Solution

13890 - Werner Keym

Die Schwalbe, October 2008

Corrected German text: In einem Illegal Cluster mit den Königen und zwei wei?#376;en Offizieren ist die Summe der Abstände der vier Steine zu ihren (nächstliegenden) Ursprungsfeldern a) minimal, b) maximal. Umwandlungsfiguren sind in keinem Fall zulässig.

Translation of corrected text: In an Illegal Cluster with both kings and two white officers, the sum of the distances of the four pieces to their (closest) home square is a) minimal b) maximal. In no case promoted pieces are allowed.

Solution