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Probleemblad

January 2003

R189 - Joost de Heer

Probleemblad, January 2003

1. d3 d6 2. Bg5 Be6 3. Bxe7 Nd7 4. Bxd6 Qh4 5. Bxc7 Ne7 6. Bg3 O-O-O 7. f4 Kb8 8. f5+ Ka8 9. f6 Nc8 10. fxg7 Bd6 11. g8=Q Bb8 12. Qxf7 Rhe8 13. Qxh7 Bg8 14. Qf7 Qh8 15. Bc7 Nf8

Optical cyclical shift of all black pieces over distance 4. This is anticipated by G. Wicklund, Springaren june 2001,

[kbnrrnbq/pp6/8/3p4/8/1P4B1/P1PPPRPP/RN1QKBNR] (16+11) SPG 15.0


R190 - Dan Meinking

Probleemblad, January 2003

dedicated For Cecilia

1. Nc3 b5 2. Ne4 Bb7 3. Ng3 Bf3 4. c4 Bg4 5. Nf3 e6 6. Rg1 Bb4 7. Nh1 c5 8. g3 Nc6 9. Bg2 Rb8 10. Kf1 Rb6 11. Ne1 Ra6 12. Be4 Ra3 13. Bc2 Rc3 14. b3 Nge7 15. Bb2 O-O 16. Qc1 Qe8 17. Bd1 Rc2 18. Rb1 Bc3 19. Ba1

Cyclical platzwechsel of all white officers


R191 - Unto Heinonen

Probleemblad, January 2003

1. c4 a5 2. c5 a4 3. c6 a3 4. cxb7 axb2 5. a4 f5 6. Ra3 f4 7. Rg3 f3 8. Nc3 b1=N 9. Ba3 fxg2 10. Bd6 exd6 11. f4 Qh4 12. f5 g5 13. f6 Bg7 14. f7+ Ke7 15. f8=B+ Ke6 16. Be7 Bd4 17. Bd8 Ne7 18. a5 Rf8 19. a6 Rf3 20. a7 Na6 21. b8=R Bb7 22. Rc8 Rb8 23. a8=B Ba7 24. d4 Nd2 25. Nb1 Rc3 26. Nf3 g1=N 27. Bg2 Nf1 28. Nfd2 Bf3 29. Bb7 Ra8 30. Rb8

From black's 20th move on every move is to the just departed square (Umnov)


R192 - Wolfgang Dittmann

Probleemblad, January 2003

-1. Ke1xPf2[Ke1] f3-f2 -2. Kg4xPf5[Ke1] g7-g5 -3. g2xBh3[h2] Rc8-c2 -4. h2xRg3[g2] Ra8-a6 -5. g5xNh6[h2] Ng8-h6 -6. Re2-e8 and 1. Ra2#

To mate on a2, c8 and g8 must be blocked so Bb3 and Nb4 can't capture.


R193 - Wolfgang Dittmann

Probleemblad, January 2003

Main plan: -1. Kf4xNe5[Ke1] and 1. h8=Q. But this fails on Rh5. Try: -1. Ke1xBf2[Ke1]? Bc5-f2 -2. Ke1xBf2[Ke1] Bf8-c5!. So first the diagonal c5-f8 must be closed:

-1. Ke2xBf2[Ke1] e7-e6 (d4-d3 leads to a shorter mate, because the black bishop can't reach c5 anymore) -2. Ke1-e2 Bg1-f2 and now -3. Ke1xBf2[Ke1] Bc5-f2 -4. Ke1xBf2[Ke1] Bd4-f2 -5. Ke1xBf2[Ke1] Be3-f2 -6. Ke1xBf2 Rf8-f5 and now the main plan works: -7. Kf4xNe5[Ke1] and 1. h8=Q#


R182c - Klaus Wenda, Wolfgang Dittmann

Probleemblad, January 2003

-1. Ke1xBd2[Ke1] Bc1-d2 -2. Ke1xBd2[Ke1] Be3-d2 -3. c7xBb8=N[Ng1]! ~ (c2-c1=B is illegal!) -4. Kf8xRg7[Ke1] and 1. Re1 Ka1[Ke8]/ba1=R[Rh8]/Ra1[Rh8]#


179iii - Frank Christiaans

Probleemblad, January 2003

If white may castle, then Rd7 is a promoted rook. It either escaped the 8th rank through h8, f8, e8 or d8 (and then black can't castle because either his king or rook moved), or via b8 (and then black can't castle, because his last move must've been with king or rook). So castlings are mutually exclusive. 1. Rad1? OO! 1. OOO [2. Re7 Kf8 3. Rd8#] Kf8 2. Rg7 [3. Rd8#], 1...gf6 2. Rd8 Ke7/f7 3. R1d7#.