# Phénix

No. 117, April 2003 - SOLUTIONS

4211 - J. M. Chorein
Phénix 117, April 2003

Try: 1.0-0 Bc8 2.Rd8 Bxe6 mat ? But Blacks have lost the right to castle! The black Queen Bishop has been captured on b3 by Pc2xBb3 (only possibility) The Sb1 has been captured by the King or the black Queen Bishop. To have access to b1 with a bishop or a King, we must have c2xFb3 before. So the black King has captured the Sb1 and the black O-O is now impossible. Solution : 1.Rf7 ! Fç8 2. Rg8 Fxe6 #.

Proof game example: 1.f4 e5 2.fxe5 Bc5 3.d4 Bxd4 4.Bh6 Bxg1 5.Bxg7 Bxh2 6.Bf6 Bxe5 7.Bxd8 Bxb2 8.Bxc7 Bxa1 9.Bxb8 Bd4 10.Bxa7 Bxa7 11.Qd3 Bc5 12.Qg6 Ra4 13.Qxg8+ Bf8 14.g4 Rxg4 15.e4 Rxe4+ 16.Qg6 d5+ 17.Bd3 Bf5+ 18.Qe6+ fxe6+ 19.Bxe4 Bh6 20.Bd3 Bd2+ 21.Kxd2 Kf7 22.Rh3 Kg6 23.Ba6 b5 24.Rb3 Bd3 25.Ke1 Bc4 26.Bb7 Bxb3 27.cxb3 Kf5 28.Ba6 Ke4 29.Bb7 Kd3 30.Ba6 Kc2 31.Bb7 Kxb1 32.Ba6 Kc2 33.Bb7 Kd3 34.Ba6 Ke4 35.Bb7 Kf5 36.Ba6 Kg6 37.Bb7 Kf7 38.Bc8 Ke8 39.Ba6

4212 - J. F. Baudoin
Phénix 117, April 2003

Try: 1.h4 O-O 2.Kg3 Qxh2# ?? but the O-O is illegal because Whites have no last move!

Solution: 1.Re2+ Kf1 2.Re4 Qf2#

4213 -  J. M. Chorein
Phénix 117, April 2003

Try: 1.Qg2 ? d5 ! 2.Qxd5 but O-O ! or 1.Qf5 O-O ! What piece makes the last capture on black squares ? Only the wK or the bR, and only one of the both castle is possible.

Solution: 1.O-O ! 2...Df5 ! (menacing Qe4 mat) d5 3.Qc8 mat

Proof game example: 1.c4 b5 2.Qc2 h5 3.Qh7 Bb7 4.Qxg8 Bxg2 5.Qh7 Be4 6.Bg2 Bxb1 7.Bxa8 Bxa2 8.Bg2 Bb3 9.Rxa7 Bc2 10.Rxc7 Qxc7 11.d4 Qg3 12.Bf1 Qxg1 13.Bf4 Qg5 14.Bxb8 e5 15.dxe5 Bd6 16.Bxd6 Qxe5 17.Bf8 Qxb2 18.Bxg7 Bd1 19.Qd3 Bxe2 20.Qh3 Bd3 21.Bxd3 bxc4 22.Bxb2 Rf8 23.Bg7 cxd3 24.Bh8 Rxh8 (and White can castle) or 21… Qxg7 22.Kd2 Qe5 23.Qf3 Qe1+ 24.Kxe1 bxc4 25.Qh3 cxd3 (and Black can castle).

4214 - A. Buchanan
Phénix 117, April 2003
After Gligor Denkovski

Solution: 1.Nf3 b5 2.Ne5 Bb7 3.Nxd7 Bxg2 4.Nxf8 Bxh1 5.Nxh7 Bf3 6.Ng5 Bxe2 7.Nh3 Bg4 8.Ng1 Bc8 (C+)

Thematic circuit with 8+7 moves (C+F) Improvement (2 thematic moves more) in comparison with:

Gligor Denkovski
1° recommended 3°TT Supplement The Problemist 2001-02

[rnbqkbnr/1ppppppp/8/8/1P6/7N/P1P1PPP1/RNBQK3]

1.b4 Nf6 2.Bb2 Ne4 3.Bd4 Nxd2 4.Bxa7 Nxf1 5.Be3 Nxh2 6.Bc1 Ng4 7.Rh6 Nxh6 8.Nh3 Ng8 (C+)

4215 - M. Caillaud
Phénix 117, April 2003

Solution: 1.d4 c5 2.dxc5 f6 3.Qxd7+ Kf7 4.Qxc8 Qd5 5.Qxb8 Qxa2 6.Qxa8 Qxb2 7.Rxa7 Qe5 8.Rxb7 Qxh2 9.Qa1 Qxg1 10.Rh6 Qxg2 11.Bxg2 gxh6 12.Bf3 Kg7 13.Bh5= draw (C+)

Compare with:

K. Prentos and R. Tomasevic
StrateGems 2002
(after Sam Loyd)

[5bnr/4p1pb/4Qpkr/7p/7P/8/PP1P1PP1/RNB1KBN1]

1.e4 a5 2.Qh5 Ra6 3.Qxa5 h5 4.h4 Rah6 5.Rh3 f6 6.Rb3 Kf7 7.Rxb7 Bxb7 8.Qxc7 Bxe4 9.Qxb8 Bxc2 10.Qxd8 Bh7 11.Qxd7 Kg6 12.Qe6= draw

4216 - P. Wassong
Phénix 117, April 2003
After Gerd Wilts
(This problem was later found to be cooked. See improvement with 4216v.)

Author’s solution: The only white capture by pawn is Phxg. Back Pawns make : bxa, c3xb2 and hxg. The wBf1 hasn’t been captured by the bPh because this capture takes place before g2-g3 (closing the NE cage). So we have Pb3xBa2.

Since g2-g3, Black had only pawn moves, and White must try to avoid the draw. Retro : 1.Rf5-d5 (or 1.Rd8-d5) d5-d4 2.Kc2-d3 d6-d5 3.Kd1-c2 d7-d6 4.Qb1-e4 e4-e3 5.Ba3-c5 e5-e4 6.c5-c6 e6-e5 7.c4-c5 e7-e6 8.c2-c4 c3xRb2 9.Ke1-d1 c4-c3 10.Qd1-b1 c5-c4 11.Rb1-b2 c6-c5 12.Bc1-a3 c7-c6 13.b2-b3 b3xBa2 14.a3-a4 b4-b3 15.Bb3-a2 b5-b4 16.Ba4-b3 b6-b5 17.Bc6xPa4 a5-a4 18.Bg2-c6 a6-a5 19.Bf1-g2 a7-a6 20.g2-g3 and the position is unlocked.

Analyse now this position with wRd8:

[N2R2bn/p1ppppPk/1p4pr/6pr/7b/P7/1PPPPPP1/1RBQKB1n]

La suite semble simple, mais il faut faire attention. It’s possible to evacuate the bBs, bRs and bK, let a bR on h7 and take back Ph6xQg7. This wP can go back to h4 but no more. There is now a corridor for the Rooks between b7 and h5. It’s impossible to switch the white and black Rooks. (h6xg5 gives nothing more).

The last move is: 1.Rf5-d5!

Unfortunately Perkonoja found a second way to reach the diagram, capturing the wPa with the Rook! 1.Rf5-d5 d5-d4 2.Kc2-d3 d6-d5 3.Kd1-c2 d7-d6 4.Qb1-e4 e4-e3 5.Ba3-c5 e5-e4 6.c5-c6 e6-e5 7.c4-c5 e7-e6 8.c2-c4 c3xRb2 9.Ke1-d1 c4-c3 10.Qd1-b1 c5-c4 11.Rb1-b2 c6-c5 12.Bc1-a3 c7-c6 13.b2-b3 b3xBa2 14.Ra5-f5 b4-b3 15.Rf5xPa5 a6-a5 16.Bd5-a2 a7-a6 17.Bg2-d5 b5-b4 18.Bf1-g2 b6-b5 19.g2-g3 The last move is the same (Rf5-d5) and the problem is correct, but the 39 last moves aren’t determined!

The author improves it with

4216v - Pascal Wassong

[N5bn/5pPk/2QR2pr/2K3pr/P1P1p2b/BP4P1/pp1PPP2/7n]

Solution: The 39 last single moves are determined this time and the final analyze is the same. Retro: 1.Rf6-d6 e5-e4 2.Kd4-c5 e6-e5+ 3.Kd3-d4 e7-e6 4.Kc2xPd3 d4-d3+ 5.Qe4-c6 d5-d4 6.Kd1-c2 d6-d5 7.Qb1-e4 d7-d6 8.c2-c4 c3xRb2 9.Ke1-d1 c4-c3 10.Qd1-b1 c5-c4 11.Rb1-b2 c6-c5 12.Bc1-a3 c7-c6 13.b2-b3 b3xBa2 14.a3-a4 b4-b3 15.Bb3-a2 b5-b4 16.Ba4-b3 b6-b5 17.Bc6xPa4 a5-a4 18.Bg2-c6 a6-a5 19.Bf1-g2 a7-a6 20.g2-g3 The last move is Rf6-d6!