Awarded Problems - SoLUTIONS
1 - Michel Caillaud
1. a3 d5 2. a4 d4 3. a5 d3 4. exd3 Bh3 5. Ne2 Kd7 6. Nec3 Ke6 7. Qg4 Kf6 8. Qc8 Qd5 9. Qxf8 Qf3 10. gxf3 Bc8 11. Bh3 h5 12. Bd7 Nh6 13. Ba4 Bh3 14. Qc8 Rd8 15. Qg4 Ng8 16. Qg2 Bc8
2 - Claude Beaubestre
Author's intention: 1. Nc3 h5 2. Ne4 h4 3. Ng3 hxg3 4. h3 Rh4 5. Rh2 gxh2 6. Rb1 hxg1=B 7. Ra1 Bh2 8. Rb1 Be5 9. Ra1 Bc3 10. Rb1 e5 11. Ra1 Ba3 12. Rb1 c5 13. Ra1 Qa5 14. Rb1 b6 15. Ra1 Bb7 16. Rb1 Bf3 17. exf3 a6 18. Bxa6 Nc6 19. Bf1 O-O-O 20. Ke2 Nd4 21. Kd3
Simon Foulkes later found that the problem is cooked for, as he posted to the retro-list , "the 5th Black move Rh4 could be interchanged with the 17th Black move a6. Also, if the 5th black move was a6 then the 17th black move could be not only Rh4 but also Nc6".
Joachim Coutelle found a solution in 20 moves: 1. Nc3 e6 2. Nd5 Ba3 3. Ne3 c5 4. Ng4 Qa5 5. h3 b6 6. Rh2 Bb7 7. Rb1 Bf3 8. exf3 h5 9. Qe2 hxg4 10. Qa6 g3 11. Qxa7 gxh2 12. Qa6 hxg1B 13. Qe2 Bh2 14. Qd1 Be5 15. Ke2 Bc3 16. Kd3 Nc6 17. Ra1 Nd4 18. Rb1 Rh4 19. Ra1 O-O-O 20. Rb1 e5
3 - Pascal Wassong
a) 1. e3 h5 2. Qxh5 a6 3. Qd1 Rxh2 4. Bxa6 Rh8 5. Bf1 b) 1. e3 a6 2. Bxa6 h5 3. Bf1 Rxa2 4. Qxh5 Ra8 5. Qd1
