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Europe Echecs

No. 471, Oct 1998 - SOLUTIONS

1 - F. Brassaud
EE 471, Oct 1998
Ded. André Hazebrouck

The black rook on b1 is promoted. This, combined with the pawn on b3, requires 6 captures on white squares. But there are only four white-squared pieces missing! So two black-squared pawns were captured en-passant. So black's last move couldn't have been a2xb1=R. White's last move couldn't have been Rh1xd1, because no black piece could've gotten to d1.

The only possible last move by black could've been a4xb3 ep, or c4xb3 ep. So the last move on black squares was b2-b4.


2 - A. Kisliak
EE 471, Oct 1998
Ded. André Hazebrouck 80th birthday

The position unlocks after retracting: -1. Qh1xNh2 Nf1-h2 -2. Nh2-g4 Bg6-h5 -3. Be4-b1 b6-b5 -4. Ba8-e4 b5-b4 -5. a7-a8=B b4-b3 -6. a6-a7 a7xNb6 -7. Nc4-b6 b6-b5 -8. Ne5-c4 b5-b4 -9. Ng4-e5 Bh5-g6 -10. Rg5-g7 Bg6-h5 and now the knight on g4 unpromotes on c8, and black uncaptures a bishop with c7xBb6. This bishop goes to c1, and white can uncapture d2xNe3. The black rook makes tempo-moves on g7 and g8 in the meantime.


3 - N. Plaksine & A. Zolotarev
EE 471, Oct 1998
Ded. André Hazebrouck 80th birthday

Retro-play: -1. .. f7xNe6 -2. Nd8-e6 e5xNf4 -3. d7-d8=N d6xRe5 -4. c6xRd7, and further retro-play involves a3->a8=N->f4; a4xRb3; g3->g8=R->b3; g4->g8=R->e5; h2xBg3; Bf8->g3; g7xNf6 and the whole position unlocks.
So yes, the game could have started with 1. c2-c4.


4 - P. Leroy
EE 471, Oct 1998
Ded. André Hazebrouck

1. c4 Na6 2. c5 Nc5 3. e3 Ne4 4. Bc4 Ng3 5. Be6 fe6 6. h4 Kf7 7. h5 Kf6 8. h6 Kg5 9. hg7 h5 10. Rh4 Rh6 11. Ra4 Rf6 12. b4 Nh6 13. g8=B h4 14. Bg7 h3 15. Bd3 h2 16. Bf1 h1=R 17. Ne2 Rf1#


642c - A. Zolotarev
EE 472, Oct. 1998