No. 31, February 2003 - SOLUTIONS
R75 - Bruno Kampmann, Maryan Kerhuel, Thierry le Gleuher
1. c3 c6 2. Qb3 QDa5 3. Q×f7+ Kd8 4. Q×f8+ Kc7 5. Q×c8+ Kd6 6. Q×b8+ Kd5 7. Q×g8+ Ke4 8. Q×g7 Rag8 9. Qh6 Rg3 10. f4 Rf3 11. Kd1 R×f1+ 12. Kc2 R×c1+ 13. Kb3 Q×c3+ 14. Ka4 Qb3+ 15. Ka5 b6+ 16. Ka6 Q×a2+ 17. Kb7 Qa6+ 18. Kc7 Qb7+
R76 - Alessandro Cuppini
a) -1 … a2×Rb1=B -2. h3-h4 (a3-a2 -3. Ka2-a1 a4-a3 -4. Ka3-a2 a5-a4 -5. Ka4-a3 a6-a5 -6. Ra1-b1 Kb1-c2 -7. Ra2-a1+ Bc2-d1 …)
b) -1 … a2×Nb1=B -2. Nc3-b1…
R77 - Alessandro Cuppini
White could mate in 2 moves:
1. Ke8 [2. f8=Q‡].
But Black hat the move:
1. … h×g5 (1. … g6? 2. Ke7 h×g5 (2. …g×h5 3. g6 Rg7 4. Kf6 +-) 3. h×g6 Rg7 4. Kf6 Rg8 5. g7+ +-) 2. Ke7,Ke8 Rh6 (2. … g6? 3. h×g6 Rg7 4. Kf6 Rg8 5. g7+ +-; 2. … R×h5? 3. f8=Q+ Kh8 3. Kf7 +-) 3. f8=Q+ Kh7 4. Qf5+ Kh8 (4…g6 (4…Rg6; 5. Q×g6+) 5. Qf7+ Kh8 6. Kf8 +-) 5. Q×g5 Rf6 6. Qd5 Kh7 7. Qd3+ (7. Ke8 Kh8 (7…Kh6 8. Qg8) 8. Qe4 Kg8 9. Kd8 Rf8+ =) Kg8 8. Qd8+ Kh7 9. Qc8 Rc2 10. Qe6 Rf6 11. Qe4+ Kh6 12. Qg2 Kh7 =
R78 - Rustam Ubaidullaev
1. e3 Na6 2. B×a6 b6 3. B×c8 d6 4. Be6 f6 5. B×g8 Rb8 6. B×h7 Kf7 7. Bg6+ K×g6 8. e4 Kh6
R79 - Rustam Ubaidullaev
1. h4 d6 2. Rh3 B×h3 3. g4 B×f1 4. e4 Bd3 5. c4 B×b1 6. d4 Bc2 7. Bh6 B×d1 8. f4 Ba4 9. Kf2 Bd7 10. a4 e6 11. Ra3 Ne7 12. Rb3 Nc8 13. Rb6 Be7 14. b4
R80 - Alessandro Cuppini
a) retro : -1. … Ka7-a8 -2. b7-b8=B+ Kb8-a7 -3. d7×c8=R+ …
1. e8=N! B~ 2. N×c7‡
b) 1. h8=Q! [2. Qa1‡]